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In a partial fraction decomposition, the numerator of a term with a quadratic denominator (or a power of a quadratic in the denominator) should have the ... ... <看更多>
Since I just solved this myself, here's some input: Let poly = function() for your function, although be careful to replace ^ with ** . ... <看更多>
Partial fraction decomposition ¶ · f = 1/(x**2*(x**2 + 1)) >>> f 1 ─────────── 2 ⎛ 2 ⎞ x ⋅⎝x + 1⎠ · apart(f) 1 1 - ────── + ── 2 2 x + 1 x. ... <看更多>